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Home/ Questions/Q 7616937
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T03:00:51+00:00 2026-05-31T03:00:51+00:00

I tried this example: /* itoa example */ #include <stdio.h> #include <stdlib.h> int main

  • 0

I tried this example:

/* itoa example */
#include <stdio.h>
#include <stdlib.h>

int main ()
{
    int i;
    char buffer [33];
    printf ("Enter a number: ");
    scanf ("%d",&i);
    itoa (i,buffer,10);
    printf ("decimal: %s\n",buffer);
    itoa (i,buffer,16);
    printf ("hexadecimal: %s\n",buffer);
    itoa (i,buffer,2);
    printf ("binary: %s\n",buffer);
    return 0;
}

but the example there doesn’t work (it says the function itoa doesn’t exist).

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  1. Editorial Team
    Editorial Team
    2026-05-31T03:00:52+00:00Added an answer on May 31, 2026 at 3:00 am

    Use sprintf():

    int someInt = 368;
    char str[12];
    sprintf(str, "%d", someInt);
    

    All numbers that are representable by int will fit in a 12-char-array without overflow, unless your compiler is somehow using more than 32-bits for int. When using numbers with greater bitsize, e.g. long with most 64-bit compilers, you need to increase the array size—at least 21 characters for 64-bit types.

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