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Editorial Team
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Asked: 2026-06-16T13:25:35+00:00

I tried this imagejpeg() php method, but it returns an image to a browser

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I tried this imagejpeg() php method, but it returns an image to a browser on running the code.

However I need a method that returns an image URL so that i can use it in my img tag.

Currently i have to use –

<img src="siteurl/myphpfile.php" />

but i think its better if the method returns an image handler so that i can use it in my img tag, like –

<img src="image.jpg" />

My myphpfile.php is the file that contains the code.

Searched many functions at php manuals but no luck, I am also using this method imagettftext() for text addition over image.

Total code in the File —

<?php
    function myimagecreate( $myname ) {
    $headurl = 'template_header01.jpg';
    header('Content-type: image/jpeg');
    $text = "My Full Text";
    $name = $text.".jpg";
    $jpg_image = imagecreatefromjpeg($headurl);
    $black = imagecolorallocate($jpg_image, 1, 1, 1);
    $font_path = 'myfont/arial.ttf';
    imagettftext($jpg_image, 24, 0, 175, 85, $black, $font_path, $text);
    imagejpeg($jpg_image,'mynameimg.jpg');
    imagedestroy($jpg_image);
    return 'mynameimg.jpg';
    }

    $to = 'swapnesh20032003@gmail.com';
    $subject = $myname; 
    $message = '<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Kings</title>
</head>

<body>
<table width="100%"><tr><td valign="bottom" align="center" height="282"><img src="'.myimagecreate( $myname ).'" /></td></tr></table></table></body></html>';

mail($to,$subject,$message);    
?>
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1 Answer

  1. Editorial Team

    There are 2 more obvious ways to approach this problem.

    1. Write the rendered image to a file

      This is possible using imagejpeg, by passing in a second parameter of the filename, for example:

       $im = imagecreatetruecolor(..);
 // ..
 imagejpeg($im, 'image.jpg');

    2. Use URL Rewriting

      You can always pass through all .jpgs in a special folder (for example /dynamic/image.jpg through to your script which will render it). If you want, you could even take the filename (image.jpg) as a parameter to your script telling it what to render if the image is dynamic.

    Obviously, if your image needs to be different per request, #2 is the better option. However, #1 is faster and recommended if your image is static (ie. your imagettftext always writes the same text over the same image).

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