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Home/ Questions/Q 738911
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T08:20:24+00:00 2026-05-14T08:20:24+00:00

I tried this myProcess = new Process(); myProcess.StartInfo.CreateNoWindow = true; myProcess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden; myProcess.StartInfo.FileName

  • 0

I tried this

        myProcess = new Process();

        myProcess.StartInfo.CreateNoWindow = true;
        myProcess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;

        myProcess.StartInfo.FileName = "Hello.exe";

        myProcess.StartInfo.Arguments ="-say Hello";
        myProcess.StartInfo.UseShellExecute = false;  

        myProcess.OutputDataReceived += new DataReceivedEventHandler(myProcess_OutputDataReceived);
        myProcess.ErrorDataReceived += new DataReceivedEventHandler(myProcess_OutputDataReceived);
        myProcess.Exited += new EventHandler(myProcess_Exited);
        myProcess.EnableRaisingEvents = true;

        myProcess.StartInfo.RedirectStandardOutput = true;
        myProcess.StartInfo.RedirectStandardError = true;
        myProcess.StartInfo.ErrorDialog = true;
        myProcess.StartInfo.WorkingDirectory = "D:\\Program Files\\Hello";

        myProcess.Start();

        myProcess.BeginOutputReadLine();
        myProcess.BeginErrorReadLine();

Then I am getting this error..
alt text http://img188.imageshack.us/img188/3759/errorstack.jpg

My process takes very long to complete, so I need to show progress in runtime.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T08:20:25+00:00Added an answer on May 14, 2026 at 8:20 am

    You don’t need to call ReadLine(), the line of text that was read is one of the properties passed to you in the DataReceivedEventArgs object.

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