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Home/ Questions/Q 6934455
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T11:57:44+00:00 2026-05-27T11:57:44+00:00

I tried to clone tabs element to different location by using clone(true) method but

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I tried to clone tabs element to different location by using clone(true) method but it didn’t work properly. For example, I can not switch between tabs in ‘#here’ div.

Here is the html content:

<body>

<div id="tab1" class="tabs" style="height:100px; width:300px">
    <ul></ul>
</div>

<div id="here" style="height:100px; width:300px"></div>
</body>

and this is the code which I tried:

$('#tab1').tabs({ closable: true });

$('#tab1').tabs('add', '#' + 1, 'test');
$('#tab1').tabs('add', '#' + 2, 'test');


var tmp = $('#tab1').clone(true);

tmp.appendTo($('#here'));

I don’t want to copy html tags and then reinitialize the tabs element like this:

$('#tab1').tabs({ closable: true });

$('#tab1').tabs('add', '#' + 1, 'test');
$('#tab1').tabs('add', '#' + 2, 'test');


$('#here').html($('#tab1').html());
$('#here').tabs();

I actually want to relocate tabs, which has ui elements like jqgrid, jstree in it, to different div dynamically and the above code is not appropriate solution.

thanks for your attention.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T11:57:45+00:00Added an answer on May 27, 2026 at 11:57 am

    If you want to reallocate i think you could use detach() so that you can reappend the elements later

    var tab = $('#tab1').detach();
    tab.appendTo($('#here'));
    
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