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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T22:04:51+00:00 2026-06-05T22:04:51+00:00

I tried to create a script to list the contents of a directory: #!/bin/bash

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I tried to create a script to list the contents of a directory:

#!/bin/bash
matched=$(ls -1 /data/ | grep $1)
echo $matched

I have added the parameter -1 to the ls command and when executed like this ./script dir the output is on one row:

dir1 dir2

I’ve also tried echo -e $matched, but the output was:

-e dir1 dir2

So how can I list the directories each on separate line ?

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  1. Editorial Team
    Editorial Team
    2026-06-05T22:04:52+00:00Added an answer on June 5, 2026 at 10:04 pm

    Try using double quotes around the string to be echoed:

    echo "$matched"
    

    The quotes here cause certain special characters to be preserved; see here.

    Edit: See cdarke’s comment for a better explanation.

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