Question

I tried to create one array of strings in C. Here is the code:

#include <stdio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>

int main()
{
    char *foo[100];
    strcpy(foo[0], "Testing this");
    printf("%s ", foo[0]);

    return 1;
}

But when I compile it, it simply breaks. No error, no nothing, it simply doesn’t work and breaks. Any suggestion? When I tri char *foo[10] it works, but I can’t work with just 10 strings

Answer 1

You allocated an array of pointers but did not allocate any memory for them to point to. You need to call malloc to allocate memory from the heap.

char *foo[100];
foo[0] = malloc(13);
strcpy(foo[0], "Testing this");

Naturally you would need to free the memory at some later date when you were finished with it.

Your code invokes what is known as undefined behavior. Basically anything can happen, including the code working as you intended. If the version with char *foo[10] works as you intended that’s simply down to luck.

As an aside, your main() definition is wrong. It should be int main(void).