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Home/ Questions/Q 8078999
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Editorial Team
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Editorial Team
Asked: June 5, 20262026-06-05T15:58:30+00:00 2026-06-05T15:58:30+00:00

I tried to get an answer from server and conver it to JSONObject .

  • 0

I tried to get an answer from server and conver it to JSONObject.
At Now I have this code

private JSONObject sendData(ArrayList<NameValuePair> data, String actionname)

{

    // 1) Connect via HTTP. 2) Encode data. 3) Send data.
    try

    {
        HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new      
        HttpPost(actionname);
        httppost.setEntity(new UrlEncodedFormEntity(data));
        HttpResponse response = httpclient.execute(httppost);
    //   Log.i("postData", response.getStatusLine().toString());
        InputStream is = response.getEntity().getContent();
        String result = convertStreamToString(is);

     //   JSONArray jArr = new JSONArray (result);
       // int eventID = jArr.getJSONObject(0).getInt("eventID");

        JSONObject jObject = new JSONObject(result);
        return jObject;

    }
    catch(Exception e)
    {
        Log.e("log_tag", "Error:  "+e.toString());
    }

    return null;  

}

in result string variable I have this

{“status”:{“code”:404,”text”:”Not Found”},”content”:”User
authentication failure”}

But on the string of code JSONObject jObject = new JSONObject(result); – It go to the return null; =(( I tried to create JSONArray but it return me an extention that I can create JSONARRAY from JSONObject.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-05T15:58:32+00:00Added an answer on June 5, 2026 at 3:58 pm

    I solved the problem, but I don’t understand why it so. May be I am not so good in OOP. So I create JSONObject jObject as a property of class JSONHandler, that have sendData method. And it became work. I will be happy if somebode explain me why it so.

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