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Editorial Team
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Asked: 2026-05-31T13:22:34+00:00

I tried to print the argument before $NF . However $NF– doesn’t do the

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I tried to print the argument before $NF. However $NF-- doesn’t do the trick. What is the solution to this? Problem is, I dono how many args I get, so I always need $NF and the arg before.

Kind Regards

Juergen

host -t ptr 1.1.1.1 | awk '/pointer/ {num=split($0,a, "."); print a[num-2] "." a[num-1] ;}'

foo.tld
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1 Answer

  1. Editorial Team

    You can use $(NF - 1) to get the next to last field. So in your case:

    awk '{print $(NF - 1), $NF}'
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