Question

I tried to set an inArray with an object but it don’t works

var test = {aa:1, bb:0}
console.log($.inArray(1,test))

I always have -1

thanks

Answer 1

{} = object literal

[] = array object

$.inArray is designed to work with arrays. It will not work properly with objects as you have already figured out (it returns -1 no matter the circumstance). Speaking of objects, the syntax you used to create an object literal is ill-formed, it’s not written as { a = b } but rather as { a : b }. Here is an example:

var test = { aa: 1, bb: 0 };

I also see that you’re trying to find if a property of an object has a certain value, and not that the object has the property at all. If it were the latter case we’d use the in keyword or .hasOwnProperty function. But we’ll need to make our own function for your case. Try this:

var inObject = function( obj, val ) {

    for ( var i in obj ) {

        if ( obj.hasOwnProperty(i) ) {

            if ( obj[i] === val ) return true;

        }

    }

    return false;

};

And we’ll use it like this:

>>> var test = { aa: 1, bb: 0 };

>>> inObject( test, 1 );
    true