Question

I tried to write an function that sorts arrays using pointers. My p pointer points to x array but why should I return x as a pointer?

    #include <stdio.h>
    int sort(int x[], int n){
    int *p,k;
    p=x;
    for(int i=0; i<n-1; i++){
        for(int l=i+1; l<n; l++){
            if(*(p+i)>*(p+l)){
                k=*(p+i);
                *(p+i)=*(p+l);
                *(p+l)=k;
            }
        }
    }
    return *x;
}
int main(){
    int n;
    scanf("%d", &n);
    int a[n];
    for(int i=0; i<n; i++){
        scanf("%d",&a[i]);
    }
    sort(a,n);
    for(int i=0; i<n; i++){
        printf("%d ",a[i]);
    }
    return 0;
}

Answer 1

your function returns an int (value), not a pointer. your implementation (return *x;) returns the first element of parameter x[] by value.

why should I return x as a pointer?

what is the return value supposed to indicate? it’s not clear why you would return anything in this scenario. until you can answer that, void would be better.