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Home/ Questions/Q 8546685
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T13:05:29+00:00 2026-06-11T13:05:29+00:00

I tried to write my own fib function that works for large numbers (over

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I tried to write my own fib function that works for large numbers (over 50) and I had no luck. First I tried the obvious solution but that overflows way to quicly. my next solution was this

    $fun fib(a:int, b:int, index:int) = if(index = 1) then
    $                                      (a+b)
    $                                   else
    $                                       fib(b, (a+b), index - 1);

Unfortunatly this also overflows.

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  1. Editorial Team
    Editorial Team
    2026-06-11T13:05:31+00:00Added an answer on June 11, 2026 at 1:05 pm

    You need to take a look at the IntInf module, which provides access to arbitrary precision integers.

    You can convert from Int.int to IntInf.int using IntInf.fromInt.

    Note, for any operations you do on them, you have to use IntInf.<operation> instead of the Int counterpart. This includes things like addition and the likes.

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