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Home/ Questions/Q 6076303
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:35:32+00:00 2026-05-23T10:35:32+00:00

I tried using a raycasting-style function to do it but can’t get any maintainable

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I tried using a raycasting-style function to do it but can’t get any maintainable results. I’m trying to calculate the intersection between two tangents on one circle. This picture should help explain:

enter image description here

I’ve googled + searched stackoverflow about this problem but can’t find anything similar to this problem. Any help?

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:35:32+00:00Added an answer on May 23, 2026 at 10:35 am

    Well, if your variables are:

    C = (cx, cy) - Circle center
    A = (x1, y1) - Tangent point 1
    B = (x2, y2) - Tangent point 2
    

    The lines from the circle center to the two points A and B are CA = A - C and CB = B - C respectively.

    You know that a tangent is perpendicular to the line from the center. In 2D, to get a line perpendicular to a vector (x, y) you just take (y, -x) (or (-y, x))

    So your two (parametric) tangent lines are:

    L1(u) = A + u * (CA.y, -CA.x)
          = (A.x + u * CA.y, A.y - u * CA.x)
    
    L2(v) = B + v * (CB.y, -CB.x)
          = (B.x + v * CB.y, B.x - v * CB.x)
    

    Then to calculate the intersection of two lines you just need to use standard intersection tests.

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