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Home/ Questions/Q 8909373
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T03:24:49+00:00 2026-06-15T03:24:49+00:00

I try necessaryStuffOnly = SoupStrainer(table,{class: views-table}) soup = BeautifulSoup(vegetables,parse_only=necessaryStuffOnly) without luck on a table

  • 0

I try

necessaryStuffOnly = SoupStrainer("table",{"class": "views-table"})
soup = BeautifulSoup(vegetables,parse_only=necessaryStuffOnly)

without luck on a table like this:

<div class="view-content">
  <table class="views-table sticky-enabled cols-20">
    <thead>
      <tr>
        <td>blablaba</td>
      </tr>
    </thead>
    <tbody>
      <tr>
        <td>more blablabla</td>
      </tr>
    </tbody>
  </table>
</div>

and this does work for the div

SoupStrainer("div",{"class": "view-content"})

Can’t a SoupStrainer like this filter on element with multiple classes?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-15T03:24:51+00:00Added an answer on June 15, 2026 at 3:24 am

    The comparision that’s used is a literal equality check, so the following works:

    soup('table', {'class': "views-table sticky-enabled cols-20"})
    

    You can get it to match by doing by passing a function as to the filter:

    soup('table', {'class': lambda L: 'views-table' in L.split()})
    

    It might be worth checking the version you’re using, because I have a feeling this shouldn’t be the case anymore… update: yup, here you go https://bugs.launchpad.net/beautifulsoup/+bug/410304

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