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Editorial Team
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Asked: 2026-05-28T07:27:22+00:00

I try to execute a simple SQL query in a shell script but I

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I try to execute a simple SQL query in a shell script but I had trouble because of the escape of characters

Here is the problem line

#!/bin/sh
su -l mysql -c 'mysql -h XXX.XXX.XX.XXX -uuser -padmin -D testBD -e "SELECT CASE MODE WHEN 0 THEN \'choix1\' WHEN 1 THEN \'choix2\' WHEN 2 THEN \'choix3\' END , count( * ) FROM city GROUP BY name" > /kbd/testSelect'

I have tested this, but I get errors of escaping character that I don t know how to solve
Thank you very much

line 4: syntax error near unexpected token `('
/kbd/test.sh: line 4: ` su -l mysql -c 'mysql -h XXX.XXX.XX.XXX -uuser -padmin -D testBD -e "SELECT CASE MODE WHEN 0 THEN \'choix1\' WHEN 1 THEN \'choix2\' WHEN 2 THEN \'choix3\' END , count( * ) FROM city GROUP BY name" > /kbd/testSelect''
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1 Answer

  1. Editorial Team

    A simple solution is to put the command you want to execute in a separate script:

    #!/bin/sh
mysql -h XXX.XXX.XX.XXX -uuser -padmin -D testBD -e "SELECT CASE MODE WHEN 0 THEN 'choix1' WHEN 1 THEN 'choix2' WHEN 2 THEN 'choix3' END , count( * ) FROM city GROUP BY name" > /kbd/testSelect

    Then call that script from your original script:

    #!/bin/sh
su -l mysql -c "/path/to/my_new_script.sh"
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