Question

I try to execute the following SQL-Statement (in my Java-application):

SELECT * FROM Tbl_Job WHERE jobname LIKE '%aa%';

But I can’t get the same (correct?) result using MS Access (2002):

SELECT * FROM Tbl_Job WHERE jobname LIKE '*aa*';

With this example Access will give me 400 datasets and my Java-application will only give me somewhat less I don’t know the exact number of datasets.

I tried to use the [*]-wildcard in my Java-app but it didn’t give me any datasets at all.
Besides I tried to replace the [‘]-character with the [“]-character but this didn’t work either.

I don’t know whether this is relevant or not but I think the *.mdb-file was created with MS Access (2000)

My Java code:

Class.forName("sun.jdbc.odbc.JdbcOdbcDriver");
Connection connection = DriverManager.getConnection("jdbc:odbc:_
                        Driver={Microsoft Access Driver_
                        (*.mdb)};DBQ=C:\database.mdb");
Statement stm = connection.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE,
                ResultSet.CONCUR_READ_ONLY);
ResultSet rs = stm.executeQuery(sql);
while(rs.next())
    do_some_stuff();

Answer 1

Suggest you try this SQL statement both from Java and directly in Access.

SELECT Count(*) AS num_rows FROM Tbl_Job WHERE jobname ALike '%aa%';

If num_rows is the same in both cases, change the WHERE clause in your first query to match this one.

If num_rows is not the same in both cases, please describe how they differ and which is correct.