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Home/ Questions/Q 6538049
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T10:41:22+00:00 2026-05-25T10:41:22+00:00

I try to get the upload value when the input field ‘s change event

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I try to get the upload value when the input field‘s change event occurs

But I get this value on Chrome,

C:\fakepath\winnie-the-pooh.jpg

So I split the \ and the the last item in the array.

jquery,

$("#upload").change(function(){

    var fragment = $("#upload").val();
    var array_fragment = fragment.split('\/');
    alert($(array_fragment).last()[0]);

});

But I still get C:\fakepath\winnie-the-pooh.jpg instead of winnie-the-pooh.jpg on Chrome.

How can I make it worked?

the html,

<input type="file" name="image" id="upload"/>
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-25T10:41:22+00:00Added an answer on May 25, 2026 at 10:41 am

    You need to split on \, not /:

    var array_fragment = fragment.split('\\');
    

    Ideally though, you’d split on either. Fortunately, split takes a regular expression:

    var array_fragment = fragment.split(/\\|\//);
    

    That regex basically means “\ or /“—the pipe operator, |, is the “or”, and the / characters at the start and end signify that a regular expression is in between.

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