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Home/ Questions/Q 8113801
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T02:56:54+00:00 2026-06-06T02:56:54+00:00

I try to get the whole content between an opening xml tag and it’s

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I try to get the whole content between an opening xml tag and it’s closing counterpart.

Getting the content in straight cases like title below is easy, but how can I get the whole content between the tags if mixed-content is used and I want to preserve the inner tags?

<?xml version="1.0" encoding="UTF-8"?>
<review>
  <title>Some testing stuff</title>
  <text sometimes="attribute">Some text with <extradata>data</extradata> in it.
  It spans <sometag>multiple lines: <tag>one</tag>, <tag>two</tag> 
  or more</sometag>.</text>
</review>

What I want is the content between the two text tags, including any tags: Some text with <extradata>data</extradata> in it. It spans <sometag>multiple lines: <tag>one</tag>, <tag>two</tag> or more</sometag>.

For now I use regular expressions but it get’s kinda messy and I don’t like this approach. I lean towards a XML parser based solution. I looked over minidom, etree, lxml and BeautifulSoup but couldn’t find a solution for this case (whole content, including inner tags).

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  1. Editorial Team
    Editorial Team
    2026-06-06T02:56:55+00:00Added an answer on June 6, 2026 at 2:56 am
    from lxml import etree
    t = etree.XML(
    """<?xml version="1.0" encoding="UTF-8"?>
    <review>
      <title>Some testing stuff</title>
      <text>Some text with <extradata>data</extradata> in it.</text>
    </review>"""
    )
    (t.text + ''.join(map(etree.tostring, t))).strip()
    

    The trick here is that t is iterable, and when iterated, yields all child nodes. Because etree avoids text nodes, you also need to recover the text before the first child tag, with t.text.

    In [50]: (t.text + ''.join(map(etree.tostring, t))).strip()
    Out[50]: '<title>Some testing stuff</title>\n  <text>Some text with <extradata>data</extradata> in it.</text>'
    

    Or:

    In [6]: e = t.xpath('//text')[0]
    
    In [7]: (e.text + ''.join(map(etree.tostring, e))).strip()
    Out[7]: 'Some text with <extradata>data</extradata> in it.'
    
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