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Home/ Questions/Q 8756039
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T13:58:36+00:00 2026-06-13T13:58:36+00:00

I try to initialize an array with a lambda-function called by map, and to

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I try to initialize an array with a lambda-function called by map, and to my surprize IF-ELSE is not valid inside lambda.

a = map( (lambda x: if (len(aDict[x])==m): return aDict[x] else: return false),
         aDict.keys())

This is the error I get

File "objects.py", line 63
a = map( (lambda x: if (len(aDict[x])==m): return aDict[x] else: return false),
                     ^
SyntaxError: invalid syntax

What is the reason this does not work?


EDIT:

Now I discovered the interesting alternative expression

>>> False and 'one' or 'two'
'two'
>>> True and 'one' or 'two'
'one'

Very interesting… This is One-liner expression , this is why it wor

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  1. Editorial Team
    Editorial Team
    2026-06-13T13:58:38+00:00Added an answer on June 13, 2026 at 1:58 pm

    You can’t use that syntax inside a lambda, nor can you explicitly return. Try this instead:

    lambda x, m: aDict[x] if (len(aDict[x])==m) else False
    

    Lambda functions implicitly return the value resulting from evaluating the code in them. The code has to be expressible as a single compound expression (aka a one-liner) though.

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