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Home/ Questions/Q 618841
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T18:35:26+00:00 2026-05-13T18:35:26+00:00

I try to modify /foo/bar/dir to \/foo\/bar\/dir by ruby gsub command. I test it

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I try to modify "/foo/bar/dir" to "\/foo\/bar\/dir" by ruby gsub command.

I test it in irb the result is

x = "/foo/bar/dir"

x.gsub("/","\/")

=> "/foo/bar/dir"

x.gsub("/","\\/")

=> "\\/foo\\/bar\\/dir"

Is it possible to replace “/” with “/” by gsub ?


Source of problems:

I try to execute “string in command line” and “real_path” is my variable

real_path = "/home/me/www/idata"

path = real_path.gsub("/","\\/")

=> \\/home\\/me\\/www\\/idata 

# But what I expect is \/home\/me\/www\/idata

run "sed 's/SHARE_PATH/#{path}/g' #{path}/config/sphinx.yml > #{path}/config/sphinx.tmp.yml"

result from “run” command is

"sh -c 'sed '\''s/SHARE_PATH/\\/home\\/me\\/www\\/idata\\/shared/g .... "

I need is only one back slash like

"sh -c 'sed '\''s/SHARE_PATH/\/home\/me\/www\/idata\/shared/g .... "

“run” is command from Capistrano

my solution is

use single quote instead of double quote like this

path = real_path.gsub("/",'\/') 
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  1. Editorial Team
    Editorial Team
    2026-05-13T18:35:27+00:00Added an answer on May 13, 2026 at 6:35 pm

    Yes

    irb(main):028:0> (t = x.gsub("/", "\\/")) && nil
    => nil
    irb(main):029:0> t
    => "\\/foo\\/bar\\/dir"
    irb(main):030:0> puts t
    \/foo\/bar\/dir
    => nil
    

    Your first example actually did what you wanted, but the .inspect method that irb is using is escaping backslashes, so it looked like there were extras. If you had used puts you would have seen the real result.

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