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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:58:10+00:00 2026-05-14T04:58:10+00:00

I try to read file /proc/’pid’/status, using c program. The code is as follows,

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I try to read file /proc/’pid’/status, using c program. The code is as follows, and even I use sudo to run it, the prompt still keeps throwing “Unable to open file”. Please let me know if you have any ideas on how to fix this. thanks

Richard

…

int main (int argc, char* argv[]) {  
  string line;  
  char* fileLoc;  
  if(argc != 2)  
  {  
     cout << "a.out file_path" << endl;  
     fileLoc = "/proc/net/dev";  
  } else {  
     sprintf(fileLoc, "/proc/%d/status", atoi(argv[1]));  
  }  
  cout<< fileLoc << endl;  

  ifstream myfile (fileLoc);  
  if (myfile.is_open())  
  {  
    while (! myfile.eof() )  
    {  
      getline (myfile,line);  
      cout << line << endl;  
    }  
    myfile.close();  
  }  

  else cout << "Unable to open file";  

  return 0;  
}  
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T04:58:11+00:00Added an answer on May 14, 2026 at 4:58 am

    Avoid using C strings in C++. You forgot to allocate this one. A stringstream will allocate for you and has sprintf functionality.

    int main (int argc, char* argv[]) {  
      string line;
      ostringstream fileLoc;
      if(argc != 2)  
      {  
         cout << "a.out file_path" << endl;  
         fileLoc << "/proc/net/dev";  
      } else {  
         fileLoc << "/proc/" << argv[1] << "/status";
      }  
      cout<< fileLoc.str() << endl;  
    
      ifstream myfile (fileLoc.str().c_str());  
    
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