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Home/ Questions/Q 8394699
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T20:07:29+00:00 2026-06-09T20:07:29+00:00

I try to replace directory part of file fullname in Perl. Something like: got

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I try to replace directory part of file fullname in Perl.
Something like:
got filename ‘D:\Texts1\text1’ in directory ‘D:\Texts1’, want to replace it with ‘D:\Texts2’ and then filename will be ‘D:\Texts2\text1’.

I try this code:

$filename = 'D:\Texts1\text1';
$i = 'D:\Texts1';
$o = 'D:\Texts2';
$filename =~ s'$i'$o'g;

And it does not take effect. $filename doesn’t changes.
I tried to use something like

$i = quotemeta('D:\Texts1');

but it also has not took effect.

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  1. Editorial Team
    Editorial Team
    2026-06-09T20:07:31+00:00Added an answer on June 9, 2026 at 8:07 pm

    this doesn’t interpolate

    $filename =~ s'$i'$o'g;
    

    try using / instead of ', like this:

    $filename =~ s/$i/$o/g;
    

    that should work. ' prevents string interpolation, so the variable names appear as string literals. Also, make sure to use the quotemeta like you were doing before.

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