Question

I try to understand this code:

double b = 3;
object o = b;
Console.WriteLine(o.Equals(3));//false
Console.WriteLine(o.Equals(b));//true
Console.WriteLine( o == (object)b );//false

1. Each new boxing makes different references of object b?
2. If 1. is true, why o.Equals(b) is true?
3. If Equals does not check references, why o.Equals(3) is false?

Thanks.

Answer 1

1. Yes, each time you box a value type, a new object is created. More on boxing here.
2. Equals check for value equality, not reference equality. Both o and b are the same: a double with a value of 3.0.
3. 3 here is an int, not a double, and Equals for different types doesn’t do any conversion to make them compatible, like the compiler is usually doing. o.Equals(3.0) will return true.