Question

I try use below code to load an URL.

URL url = new URL(urlstr);
HttpURLConnection connection = (HttpURLConnection)url.openConnection();
connection.setConnectTimeout(10000);
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setUseCaches(false);
InputStream is = connection.getInputStream();  //spend lots of time

Because the line InputStream is = connection.getInputStream(); will spend some time.
So I want to show a loading dialog while it loading.
I can I do it?

In AActivity, below code to call BActivity.

Intent intent = new Intent(AActivity.this, BActivity.class).addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);  
Window w = MyGroup.group.getLocalActivityManager().startActivity("BActivity", intent);  
View view = w.getDecorView();  
MyGroup.group.setContentView(view);

And BActivity is load URL and extract information.
The load code is in onCreate().

I try the answer code, the error Unable to add window -- token android.app.LocalActivityManager$LocalActivityRecord@2afe9488 is not valid; is your activity running? shows.

Answer 1

You can achieve with the aysntask showing progress dialog as follows

In Oncreate :

         new GetTask(this).execute();//taken object for asyntask class.



    class GetTask extends AsyncTask<Object, Void, String> {
     {
        ProgressDialog progressDialog;
       void GetTask(Context cntxt)
      {

      }
        @Override
    protected void onPreExecute() {
        super.onPreExecute();

        mDialog = new ProgressDialog(cntxt); //taking object for progress dialog
        mDialog.setMessage("Please wait...");
        mDialog.show(); //Displaying progressDialog
    }

    @Override
    protected String doInBackground(Object... params) {

         //do the background process

        return ""; you can return string value

    }

    @Override
    protected void onPostExecute(String result) {
        super.onPostExecute(result);

        if (mDialog != null) {
            mDialog.dismiss();//close the progress Dialog
        }

     }
      }