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Home/ Questions/Q 9294571
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Editorial Team
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Editorial Team
Asked: June 18, 20262026-06-18T21:24:16+00:00 2026-06-18T21:24:16+00:00

I tryed tu put the ajax response in a variable tu use it later

  • 0

I tryed tu put the ajax response in a variable tu use it later but it’s not work

this is my code

var retourn;    

var requestData = new Request ({
    url: 'dnscheck.php',
    async:false,
    onComplete: function(response){
        //alert(response); // this work good
        retourn = response;
    }
});

alert(retourn); // shows me undefined

mootools 1.2.4 version

Any idea how to resolve this plaise


After clearing history and trying many time, it work fine thank you Grim

var retourn;    

var requestData = new Request ({
    url: 'dnscheck.php',
    async:false,
    onComplete: function(response){
        //alert(response); // this work good
        retourn = response;
    }
});

requestData.send();
alert(retourn); // work fine
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-18T21:24:17+00:00Added an answer on June 18, 2026 at 9:24 pm

    Remember that ajax calls are asynchronous, so the code in your onComplete handler will only be executed when the call returns, while instead your final alert will be executed immediately after the code creating the request (which you must start by calling the send method, btw) – at this time the variable will always be uninitialized.

    Edit: didn’t notice you used aync: false (which is usually a bad idea btw…) – you still need to send the request though

    requestData.send();
    

    Edit(2): Also, it is best not to use the onComplete callback (it is called when the response returns, even before checking what was actually returned) – instead use the onSuccess callback, and be aware that there are many reasons that the response may fail, so you might want to define the onFailure callback as well and do something in there too.

        var retourn;    
    
        var requestData = new Request ({
            url: 'yoururl.php',
            async:false,
            onSuccess: function(response){
                retourn = response;
            },
            onFailure: function(xhr) {
                retourn = "failed";
            }
        });
    
        requestData.send();
    
                alert(retourn);
    
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