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Home/ Questions/Q 8903663
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T01:55:28+00:00 2026-06-15T01:55:28+00:00

I trying execute an trigger on mysql database. The command executes successfully, but the

  • 0

I trying execute an trigger on mysql database.
The command executes successfully, but the trigger not working.

DELIMITER #

CREATE TRIGGER generate_coupon AFTER INSERT ON order
FOR EACH ROW
BEGIN

DECLARE userid, couponvalue INT;
DECLARE couponcode VARCHAR;
SELECT idUser INTO userid FROM indication WHERE email = NEW.email;
SET couponvalue = 20;
SET couponcode = 'abc123';

INSERT INTO coupon(idUser,idOrder,couponvalue,couponcode) values(userid, NEW.id, couponvalue, couponcode);

END# 

DELIMITER ;
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  1. Editorial Team
    Editorial Team
    2026-06-15T01:55:29+00:00Added an answer on June 15, 2026 at 1:55 am

    I suspect your problem arises from the collisions between your variables couponvalue and couponcode with the same-named columns in your coupon table. As documented under Local Variable Scope and Resolution:

    A local variable should not have the same name as a table column.

    You could simplify your trigger to the following and, in so doing, avoid this problem entirely:

    CREATE TRIGGER generate_coupon AFTER INSERT ON order FOR EACH ROW
      INSERT INTO coupon
        (idUser, idOrder, couponvalue, couponcode)
      SELECT idUser, NEW.id, 20, 'abc123'
      FROM   indication
      WHERE  email = NEW.email
    ;
    
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