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Home/ Questions/Q 8665631
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T17:31:47+00:00 2026-06-12T17:31:47+00:00

I trying to resize one image from InputStream, so I use the code in

  • 0

I trying to resize one image from InputStream, so I use the code in Strange out of memory issue while loading an image to a Bitmap object but I don’t know why this code always return Drawable without image.

This one works well:

private Drawable decodeFile(InputStream f){
    try {
        InputStream in2 = new BufferedInputStream(f);
        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inSampleSize=2;
        return new BitmapDrawable(BitmapFactory.decodeStream(in2, null, o2));
    } catch (Exception e) {
        return null;
    }
}

This one does not work:

private Drawable decodeFile(InputStream f){
    try {
        InputStream in1 = new BufferedInputStream(f);
        InputStream in2 = new BufferedInputStream(f);
        //Decode image size
        BitmapFactory.Options o = new BitmapFactory.Options();
        o.inJustDecodeBounds = true;
        BitmapFactory.decodeStream(in1,null,o);

        //The new size we want to scale to
        final int IMAGE_MAX_SIZE=90;

        //Find the correct scale value. It should be the power of 2.
        int scale = 2;
        if (o.outHeight > IMAGE_MAX_SIZE || o.outWidth > IMAGE_MAX_SIZE) {
            scale = (int)Math.pow(2, (int) Math.round(Math.log(IMAGE_MAX_SIZE / 
               (double) Math.max(o.outHeight, o.outWidth)) / Math.log(0.5)));
        }

        BitmapFactory.Options o2 = new BitmapFactory.Options();
        o2.inJustDecodeBounds = false;
        o2.inSampleSize=scale;
        return new BitmapDrawable(BitmapFactory.decodeStream(in2, null, o2));
    } catch (Exception e) {
        return null;
    }
}

why one option affect the other? how its possible if I use two different InputStream and Options?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T17:31:49+00:00Added an answer on June 12, 2026 at 5:31 pm

    Actually you have two different BufferedInputStream but they internally use the only one InputStream object because BufferedInputStream is only a wrapper for InputStream.

    So you can’t just call two times BitmapFactory.decodeStream method on the same stream, it will definitely fail because the second time it wouldn’t start decoding from the beginning of the stream. You need to reset your stream if it is supported or reopen it.

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