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Home/ Questions/Q 7715529
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T02:24:29+00:00 2026-06-01T02:24:29+00:00

I understand that in general it is a bad idea to start a new

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I understand that in general it is a bad idea to start a new thread in a constructor because it could let this escape before it is fully constructed. For example:

public final class Test {

    private final int value;

    public Test(int value) throws InterruptedException {
        start();
        this.value = value;
    }

    private void start() throws InterruptedException {
        for (int i = 0; i < 10; i++) {
            new Thread(new Runnable() {

                @Override
                public void run() {
                    System.out.println("Construction OK = " + Boolean.toString(Test.this.value == 5));
                }
            }).start();
        }
    }

    public static void main(String[] args) throws InterruptedException {
        Test test = new Test(5);
    }
}

This prints (obviously not the same every run):

Construction OK = false
Construction OK = false
Construction OK = false
Construction OK = false
Construction OK = false
Construction OK = false
Construction OK = false
Construction OK = true
Construction OK = true
Construction OK = true

Now IF the start method is the last statement of the constructor AND reordering is prevented by using a synchronized block around the final value initialisation, is there still a risk associated with starting threads from the constructor?

public Test(int value) throws InterruptedException {
    synchronized (new Object()) { // to prevent reordering + no deadlock risk
        this.value = value;
    }
    start();
}

EDIT
I don’t think this has been asked before in the sense that the question is more specific than just “Can I start threads in a constructor”: the threads are started in the last statement of the constructor which means the object construction is finished (as far as I understand it).

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T02:24:31+00:00Added an answer on June 1, 2026 at 2:24 am

    In this particular case I would consider marking value as volatile (or use AtomicBoolean) and start the threads after the value is set:

    this.value = value;   // this.value.set(value)  if using AtomicBoolean
    start();
    

    If going for this slightly dodgy solution, I would make the class final as well, to avoid the problem described by Andreas_D.


    Regarding your edit:

    […] which means the object construction is finished (as far as I understand it).

    That’s right, but consider the following scenario:

    Your test-threads are slightly more complex, and accesses a list testList of tests. Now if you do

    testList.add(new Test());
    

    the thread started in the constructor may not find the associated test in the list, because it has not yet been added. This is avoided by instead doing

    Test t = new Test();
    testList.add(t);
    t.start();
    

    Related question:

    • calling thread.start() within its own constructor
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