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Home/ Questions/Q 7635469
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T07:26:01+00:00 2026-05-31T07:26:01+00:00

I understand that this double grade(int &hw) {} is passing an argument by reference.

  • 0

I understand that this

double grade(int &hw) {}

is passing an argument by reference. And that this

double a;
double &b = a;

is making b a reference to a.

But what about this

istream &read_hw(istream &in) {}

What does the reference operator before the name of the function signify, and in what cases would the effect be desired?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T07:26:03+00:00Added an answer on May 31, 2026 at 7:26 am

    This is the type of the return value. In that case, a istream & is returned, so a reference to an istream object.

    This is desired if the returned value is meant to be modified by the caller. E.g. you can return a reference to an member variable to make it modifyable

    class X {
    private:
      int i_;
    public:
      int &i() {return i_;}
      const int &i() const {return i_;}
    };
    

    In such a case, the member i() can be used as getter and setter:

    X x;
    int a = x.i();
    x.i() = 10;
    

    In the your case of iostreams, the method returns a reference to the passed-in istream object, to enable chaining, e.g. like cout << a << b << c, which calls 3 times
    ostream &operator << (ostream &, <whatever>)

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