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Home/ Questions/Q 523601
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T08:28:46+00:00 2026-05-13T08:28:46+00:00

I understand that when we insert values into the STL map, a copy is

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I understand that when we insert values into the STL map, a copy is made and stored.
I have code that essentially does a find on the map and obtains an iterator.

I then intend to use the iterator to change the value in the map.
The results are not what I would expect ie: the value is not changed when accessed from another part of the program. I suspect its because the change I am applying is to a copy of
value.
the relevant code is as follows.

ObjectMappingType::iterator it = objectMapping_.find(symbol);

if (it == objectMapping_.end()) {
    throw std::invalid_argument("Unknown symbol: " + symbol);
}
get<3>(it->second) = value;

NOTE: I am actually trying to change a value inside a boost::tuple that is stored as the ‘value’ part of the map.

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  1. Editorial Team
    Editorial Team
    2026-05-13T08:28:46+00:00Added an answer on May 13, 2026 at 8:28 am

    Hmm… both methods seem to work fine for me. Here’s the entire example that I used:

    #include <iostream>
    #include <map>
    #include <string>
    #include <boost/tuple/tuple.hpp>
    
    typedef boost::tuple<int, std::string> value_type;
    typedef std::map<int, value_type> map_type;
    
    std::ostream&
    operator<<(std::ostream& os, value_type const& v) {
        os << " number " << boost::get<0>(v)
           << " string " << boost::get<1>(v);
        return os;
    }
    
    int
    main() {
        map_type m;
    
        m[0] = value_type(0, "zero");
        m[1] = value_type(0, "one");
        m[2] = value_type(0, "two");
    
        std::cout
            << "m[0] " << m[0] << "\n"
            << "m[1] " << m[1] << "\n"
            << "m[2] " << m[2] << "\n"
            << std::endl;
    
        boost::get<0>(m[1]) = 1;
    
        map_type::iterator iter = m.find(2);
        boost::get<0>(iter->second) = 2;
    
        std::cout
            << "m[0] " << m[0] << "\n"
            << "m[1] " << m[1] << "\n"
            << "m[2] " << m[2] << "\n"
            << std::endl;
    
        return 0;
    }
    

    The output is exactly what I would have expected.

    lorien$ g++ -I/opt/include -gdwarf-2 foo.cpp 
    lorien$ ./a.out
    m[0]  number 0 string zero
    m[1]  number 0 string one
    m[2]  number 0 string two
    
    m[0]  number 0 string zero
    m[1]  number 1 string one
    m[2]  number 2 string two
    lorien$
    
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