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Home/ Questions/Q 8792803
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T23:01:55+00:00 2026-06-13T23:01:55+00:00

I understand this code is not legal: class Popcorn { public void pop() {

  • 0

I understand this code is not legal:

class Popcorn {
    public void pop() {
        System.out.println("popcorn");
    }
}

class Food {
    Popcorn p = new Popcorn() {
        public void sizzle() {
            System.out.println("anonymous sizzling popcorn");
        }
        public void pop() {
            System.out.println("anonymous popcorn");
        }
    };
    public void popIt() {
        p.pop(); // OK, Popcorn has a pop() method
        p.sizzle(); // Not Legal! Popcorn does not have sizzle()
    }
}

What then is a way to invoke the sizzle method at all?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T23:01:56+00:00Added an answer on June 13, 2026 at 11:01 pm

    The anonymous class’s method must override/implement a method of its superclass to be accessible from the outside. There is no way around writing more boilerplate to achieve your goal, unfortunately.

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