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Home/ Questions/Q 985899
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T05:14:10+00:00 2026-05-16T05:14:10+00:00

I understand, using srand(time(0)), helps in setting the random seed. However, the following code,

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I understand, using srand(time(0)), helps in setting the random seed. However, the following code, stores the same set of numbers for two different lists.

Wondering, how do I generate the different set of numbers when the following function gets called more than once.

void storeRandomNos(std::list<int>& dataToStore)
{

    int noofElements = 0;
    srand(time(0));


    noofElements = (rand() % 14 ) + 1;

    while ( noofElements --)
    {
        dataToStore.push_back(rand() % 20 + 1 );
    }
}

Here is the rest of the code.

void printList(const std::list<int>& dataElements, const char* msg);
void storeRandomNos(std::list<int>& dataToStore);
int main()
{
    std::list<int> numberColl1;
    std::list<int> numberColl2;


    storeRandomNos(numberColl1);
    storeRandomNos(numberColl2);

    printList(numberColl1 , "List1");
    printList(numberColl2 , "Second list");


}


void printList(const std::list<int>& dataElements, const char* msg)
{

    std::cout << msg << std::endl;
    std::list<int>::const_iterator curLoc = dataElements.begin();

    for ( ; curLoc != dataElements.end() ; ++curLoc)
    {
        std::cout << *curLoc << ' ';
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-16T05:14:11+00:00Added an answer on May 16, 2026 at 5:14 am

    do the srand(time(0)) once at the beginning of your program.

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