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Home/ Questions/Q 8188367
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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T02:53:13+00:00 2026-06-07T02:53:13+00:00

I understand what a double exclamation mark does (or I think I understand) but

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I understand what a double exclamation mark does (or I think I understand) but I am not sure how it is defined on a random object. For example in the code snippet below:

Assignment *a;
if (!getAssignment(query, a))
   return false;
hasSolution = !!a;

if (!a)
   return true;

How do I know what value will the double exclamation mark result in ? In other words does it always convert to true ? false ? or can you define a behavior for it such as executing a method to determine the result (how does the object know how to act in this situation) ? I am bit confused about this piece of code due to all these exclamation stuff going on.. Any explanation is appreciated.

Hope I was clear and thanks.

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  1. Editorial Team
    Editorial Team
    2026-06-07T02:53:15+00:00Added an answer on June 7, 2026 at 2:53 am

    a is a pointer. In C++, nullptr is defined to be an invalid pointer. !pointer turns a nullptr pointer into true and a non nullptr pointer into false. !boolean turns true into false and false into true. It will always work.

    !(!a) is a useful way to think of it.

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