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Editorial Team
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Asked: 2026-06-02T16:49:28+00:00

I use a comment box in my web page and saved user input comments.

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I use a comment box in my web page and saved user input comments. Now what I want is to display them using AJAX. I set a javascript timer to get comments one by one. But I don’t know how to use AJAX to retrieve data. This is the php file

<?php
$link = mysql_connect("localhost","root","");
mysql_select_db("continental_tourism");
$query = "SELECT comment_id from comment";
$result = mysql_query($query);
$counter = 0;
while ($row = mysql_fetch_assoc($result))
{
$counter++;
} 

$comment_number = rand(1,$counter);
$query_comment = mysql_query("SELECT * FROM comment WHERE comment_id = '$comment_number'");
if (!$query_comment) { 
die('Invalid query: ' . mysql_error());
}   
while($result_comment = mysql_fetch_array($query_comment)) {

echo $result_comment['comment'];

}
?>

following is the script part in the main file.

function timeMsg()
{
var t=setTimeout("show_comment()",3000);
}

function show_comment(){

}

How should i write the AJAX code to the?

function show_comment()

If someone can explain the AJAX code line by line, I’ll be great full.

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1 Answer

  1. Editorial Team

    You have to move your all php script to another php file say getdata.php and use your ajax function in your file where you want to show the data say it is index.php. (this is for easy to use code). Now your index.php file should look like

    <html>
  <body>
    <div id="comments"></div>
  </body>
  <script src="include/jquery.js" type="text/javascript"></script>
  <script type="text/javascript>
    function show_comments() {
         $.ajax({
            url:getdata.php
            success:function(data){
               $("#comments").append(data);
            }
         }); 
  </script>
 </html>

    I am using jquery.ajax function of jquery. This is some hint how you can do this. I hope it will help you to accomplish your task.

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