Question

I use a javaBean in my jsp-application to store form values. This is how I get my values into my bean. This code is part of my form.jsp

try {  
        <jsp:setProperty name="formparam" property="*" />  
}  
catch (Exception e){ error = true; }

I left the “<%” out to not break the code display on stackoverflow. Now I get my exception if for example one puts text in my age field so the type conversation throws an exception.

Now I would like to know if it is possible to throw an exception in the setter of my bean an catch it with the very same try-catch-block.

Example form my bean: (I know this doesn’t even compile but I hope you get an idea of what I want)

public void setAge(int a) {  
    if (this.validAge(a))  
        age = a;  
    else  
        throw Exception;  
}

I hope I get my point across. Of cause it’s possible to call the validAge()-function in my bean from the form.jsp to validate the value but if I could throw an Exception directly so that the form.jsp can catch it it would be so much slicker.

So long.
mantuko

Answer 1

1) declare the exception to be thrown
2) “throw new Exception”

public void setAge(int a) throws Exception {
  if (this.validAge(a))
    age =a ;
  else 
    throw new Exception("...")
}