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Home/ Questions/Q 9155303
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T12:34:03+00:00 2026-06-17T12:34:03+00:00

I use AFNetworking as my connection lib to my app. Due to the back-end

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I use AFNetworking as my connection lib to my app. Due to the back-end restrictions, I cannot send two request simultaneously when the app starts because the server will identify a CookieTheftException (Grails). After a first successful connection, I can do as many simultaneous requests as I want but the first need to be serial.
How can I achieve that?

I thought using a Semaphore but i can’t block the main thread.

Edit 1

I tried to override but it didn’t work. I think the operation queue doesn’t wait one request to finish (including it’s callback) to start the other.

- (void)enqueueHTTPRequestOperation:(AFHTTPRequestOperation *)operation
{
    [self.operationQueue setMaxConcurrentOperationCount:1];
    [super enqueueHTTPRequestOperation:operation];
}

Edit 2

I realized that the maxConcurrentOperation worked and in fact 1 operation is executed at a time. The problem is that the request enqueued is already created without the cookies the server needs.

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  1. Editorial Team
    Editorial Team
    2026-06-17T12:34:04+00:00Added an answer on June 17, 2026 at 12:34 pm

    I don’t know anything about Grails or the specific architecture of your system, but perhaps this could be solved by simply turning off cookies on that request, with NSMutableURLRequest -setHTTPShouldHandleCookies:.

    Other than that, the best way to ensure that only one request operation is ever running for that initial call would be to ignore queues altogether, and simply have an AFHTTPRequestOperation property on your AFHTTPClient subclass. You could even get fancy with KVO to ensure that the operation queue is suspended until that initial request is finished.

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