I use asmx web service for android client application. I need soap_action, method_name, namespace and url for sample SOAP 1.1 request that written below. How can i bring out these parameters for any webservice request? The point i want to learn where these parameters come from. (ex: method_name=”GetKullaniciBilgileri” it comes from after body tag)
POST /WebSite1/WebService.asmx HTTP/1.1
Host: localhost
Content-Type: text/xml; charset=utf-8
Content-Length: length
SOAPAction: "http://kodmerkezi.net/HelloThere"
<?xml version="1.0" encoding="utf-8"?>
<soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/">
<soap:Body>
<HelloThere xmlns="http://kodmerkezi.net">
<name>string</name>
</HelloThere>
</soap:Body>
</soap:Envelope>
and i run these service as
http://localhost:56053/WebSite1/WebService.asmx?op=HelloThere
Namespace =
"http://kodmerkezi.net"SOAP_Method =
"HelloThere"SOAP_Action =
"http://kodmerkezi.net/HelloThere"URL =
"http://localhost:56053/WebSite1/WebService.asmx"It is actually easy to extract these fields if you have the WSDL.
SOAPAction is already mentioned in the WSDL and hence you can use it from there.
SOAPAction = Namespace + MethodName
Hence, form the SOAPAction, use the first part (the part with the http://…) as the namespace and the second part as the SOAPMethod.
Also, MethodName comes after the
Bodytag which is then followed by the namespace.You can get these two from here and then use SOAP_Action = Namespace + MethodName to get the SOAPAction.
Lastly, the URL refers to the URL of the *.asmx file from where you are running the service.