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Home/ Questions/Q 8600595
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T01:39:07+00:00 2026-06-12T01:39:07+00:00

I use below code to post a photo on wall usually $attachments = array(

  • 0

I use below code to post a photo on wall usually

$attachments = array( 
            'message' => $mess,
             'access_token' => $access_token
          );
$facebook->setFileUploadSupport(true);
$attachments['image'] ='@'.realpath($filename);
$photoz = $facebook->api('/'.$aid.'/photos', 'POST', $attachments);

I use Google app engine, so above wont work, so i followed below method

  $filename ="prof.jpg";
  $im ='@'.realpath($filename);
   $post = "https://graph.facebook.com/".$aid."/photos?access_token=".$access_token."&message=hellohi&source=".$im."&method=POST";
 $upload = fetch_url($post);
    echo $upload;

But when i get the error #324) Requires upload file”,”type”:”OAuthException”,”code”:32

Can i know what is the reason?and where am i wrong?

p.s – $im returns @/base/data/home/apps/s~myphotoapp/1.362007154292719350/prof.jpg

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  1. Editorial Team
    Editorial Team
    2026-06-12T01:39:08+00:00Added an answer on June 12, 2026 at 1:39 am

    But when i get the error #324) Requires upload file","type":"OAuthException","code":32

    Can i know what is the reason?

    Simple: You did not actually upload a file as an HTTP upload.

    The data has to be encoded in a format known as multipart/form-data – whereas you are just putting the parameters into an URL, which is something different.

    So either you go and do some research, how to send data as multipart/form-data within the scope of techniques Google App Engine offers you;

    or … if your images publicly are accessible via HTTP, you can also switch the source parameter for a parameter called url, in which you give the HTTP URL under which the image is retrievable.

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