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Home/ Questions/Q 8859427
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T15:03:36+00:00 2026-06-14T15:03:36+00:00

I use below code to test arc and help to understand the ARC NSArray

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I use below code to test arc and help to understand the ARC

NSArray __strong*  myArray = [NSArray arrayWithObjects:@"123", nil];
NSArray __weak*  yourArray = myArray;
NSArray __unsafe_unretained*  theirArray = yourArray;
myArray = nil;
NSLog(@"yourArray = %@, theirArray = %@", yourArray, theirArray);

As my understand, the log should be:yourArray = (null), theirArray = (null)
In face the log is:
yourArray = (
123
), theirArray = (
123
)

if I change the code and remove the __unsafe_unretained:

NSArray __strong*  myArray = [NSArray arrayWithObjects:@"123", nil];
NSArray __weak*  yourArray = myArray;
//NSArray __unsafe_unretained*  theirArray = yourArray;
myArray = nil;
NSLog(@"yourArray = %@", yourArray);

the log is right:yourArray = (null)

why if I add __unsafe_unretained local variables to weak reference my NSArray object, it like retain or strong my NSArray object.

Any one can help to answer the doubt.

Best Regards

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  1. Editorial Team
    Editorial Team
    2026-06-14T15:03:38+00:00Added an answer on June 14, 2026 at 3:03 pm

    The compiler is pretty good about figuring out what object’s lifetimes are during this kind of simple example with limited scope. It can tell that it shouldn’t release the array until the end of the scope is reached (or at least the end of the last read is reached with these simple assignments).

    If you use an ivar that’s marked __unsafe_unretained, assign it after the weak assignment, and build with full optimizations, you might see different results, even in this kind of simple case. Also, basically while the compiler may be able to deal with situations like this, where the __weak variable is still set and the __unsafe_unretained variable is still able to be read without disaster, the point is that you can’t count on it to behave that way. What you can count on is that a __weak variable will be nil’d out after its last __strong reference goes away, and that the compiler won’t insert retain/release directives for an __unsafe_unretained variable. As long as you follow the rules, you will have predictable results. As soon as you don’t follow the rules, anything that happens or doesn’t happen is undefined… so it may work in the simulator and iPod 4G’s but fail horribly on 4S and 5 while working half the time on any iPad… the point is, the result is undefined.

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