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Home/ Questions/Q 7180181
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T17:17:38+00:00 2026-05-28T17:17:38+00:00

I use C++ and swig to do some calculations. To simplify it, lets assume

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I use C++ and swig to do some calculations. To simplify it, lets assume it looks like this:

struct TestIt{
  TestIt(float x):x(x){};
  inline float& getIt() {return x;};
  float x;
};

Now I want to use the the getIt() function and print the float value.

With

testee = matching.TestIt(42)
print(testee.getIt())

I get

<Swig Object of type 'float *' at 0x1cb1690>

which makes sense, because getIt returns a reference. How can I dereference it/get a python float out of it (without changing the c++ code)?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T17:17:39+00:00Added an answer on May 28, 2026 at 5:17 pm

    Have a look here and here. You’d write something like this in your SWIG module:

    %pointer_class(float, floatp)
    

    That will let you do this in your Python code:

    print(testee.getIt().value())
    

    You will need to change your SWIG module, or write one if you are swigging the C++ header file directly. But you can probably get away with simply including your C++ header from there.

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