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Home/ Questions/Q 8982027
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T20:28:55+00:00 2026-06-15T20:28:55+00:00

I use C++ for embedded programming. Supposing I have to implement a strictly-defined (i.e.

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I use C++ for embedded programming.

Supposing I have to implement a strictly-defined (i.e. byte-by-byte) class type, can I add a constructor and some other non-virtual methods to it without objects of that type changing at the byte level? That is, can I assume that no additional data will be added to it?

I assume that RTTI is turned off.

I would like to be sure wheteher C++ standard defines this.

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  1. Editorial Team
    Editorial Team
    2026-06-15T20:28:56+00:00Added an answer on June 15, 2026 at 8:28 pm

    Yes, if you only add constructors and/or non-virtual methods you will not change the size or the layout of the class, because the original class and the new class will be layout compatible (9.2 Class members [class.mem] #17), but only if they are standard-layout classes.

    The standard-layout classes are defines as:

    9 Classes [class]

    A standard-layout class is a class that:

    — has no non-static data members of type non-standard-layout class (or
    array of such types) or reference,

    — has no virtual functions (10.3) and no virtual base classes (10.1),

    — has the same access control (Clause 11) for all non-static data
    members,

    — has no non-standard-layout base classes,

    — either has no non-static data members in the most derived class and
    at most one base class with non-static data members, or has no base
    classes with non-static data members, and

    — has no base classes of the same type as the first non-static data
    member.

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