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Home/ Questions/Q 975435
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:35:05+00:00 2026-05-16T03:35:05+00:00

I use CodeIgniter as my web application framework. I used a simple Try/Catch and

  • 0

I use CodeIgniter as my web application framework. I used a simple Try/Catch and I sent a sample value to test it, and it failed!

I know I can use $this->db->escape() function to solve my data problem but I just want to know: Why TRY/CATCH can not catch this error!

Controler code:

    $this->load->model('user_model');
    $result = $this->user_model->test_user("tes'ti");

Model code:

function test_user($username){
    try {
        $query_str = "SELECT * FROM tbl_user WHERE username = '".$username."'";
        $result = $this->db->query($query_str);
        return $result;

    } catch (Exception $e) {
        return;

    }
}

Output:

A Database Error Occurred

Error Number: 1064

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'ti'' at line 1

SELECT * FROM tbl_user WHERE username = 'tes'ti'

Let me know, where I made a mistake, if I did!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:35:06+00:00Added an answer on May 16, 2026 at 3:35 am

    You need to throw an exception if there was some mysql error:

    try {
        $query_str = "SELECT * FROM tbl_user WHERE username = '".$username."'";
        $result = $this->db->query($query_str);
    
        if (!$result)
        {
          throw new Exception('error in query');
          return false;
        }        
    
        return $result;
    
    } catch (Exception $e) {
        return;
    }
    
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