Question

I use getimagesize to judge an image height and size.

When a url has space, the getimagesize echo’s an error. I’ve tried using urlencode() to transfer all the url address, it still returns an error. I noticed that if I just change the space into %20, getimagesize runs ok.

I have no idea why?

I also tired to use $newurl = preg_replace(' ', '%20', $url); It echo’ed :

Warning: preg_replace() [function.preg-replace]: Empty regular expression

So how to preg_replace correctly. And is there a way to transfer the url correctly with getimagesize so that it passes all possible test cases.

Thanks

Answer 1

you should use str_replace(' ', "%20", $url) instead of preg_replace(' ', '%20', $url);