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Home/ Questions/Q 8480459
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T19:18:02+00:00 2026-06-10T19:18:02+00:00

I use mongoengine, and love it very. now I work it with django, and

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I use mongoengine, and love it very.
now I work it with django, and I get a problem with it
how to set property for ListField
e.g.
this was my model

class Bussiness(Document):
    tags = ListField(StringField())

and I want to use it on template like this:

{% for tag on bussiness.tags %}
    {{ tag.url }}
{% endfor %}

but the tag.url I don’t want to save it to database, just hope to produce it on model level, and make tags only some string on database.
And if I hard code it on template, I have to write it everywhere, that was I disgust.

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  1. Editorial Team
    Editorial Team
    2026-06-10T19:18:03+00:00Added an answer on June 10, 2026 at 7:18 pm

    This wont work as tag is just a string (you have it defined as a StringField).

    You could have tag as an embedded document with url being a property eg:

    class Tag(EmbeddedDocument):
        name = StringField()
    
        @property
        def url(self):
            return "http://my-ace-site.come/businesses/%s/"
    
    class Business(Document):
        tags = ListField(StringField())
    
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