Question

I use mule-standalone-3.3.0 CE. I create pattern web service proxy, and my config:

<pattern:web-service-proxy name="WebService"
    wsdlLocation="http://www.tset.com/WebService/Tse.asmx?WSDL"
    inboundAddress="http://localhost:8084/test"
    outboundAddress="http://www.tset.com/view" />

I want to put username and password on my new wsdl (http://localhost:8084/test?wsdl).
What is the best way for do that?
I know some way such as: “using spring security” but I don’t know this way is good or no.
and I have a problem about spring security:
I don’t know how to set SoapUi? I don’t know how to send authentication headers within my soapUI?

Answer 1

The web service pattern can be defined in an extended way that allows the definition of child elements. By using it you will be allowed to define the security filter leveraging spring security

Your pattern configuration should look like the following:

<pattern:web-service-proxy name="WebService"
         wsdlLocation="http://www.tset.com/WebService/Tse.asmx?WSDL">
        <http:inbound-endpoint address="http://localhost:8084/test" >
            <mule-ss:http-security-filter realm="mule-realm"/>
        </http:inbound-endpoint>
        <http:outbound-endpoint address="http://www.tset.com/view" />
</pattern:web-service-proxy>