Question

I use spring 3.0 and I have a really simple question but didn’t find any answer on the internet. I want to generate a path (an URI) just like in my JSPs:

<spring:url value="/my/url" />

But inside a controller. What is the related service to use?
Thanks!

Edit: May it be related with this: http://static.springsource.org/spring/docs/3.0.x/spring-framework-reference/html/resources.html#resources-resourceloader ?
Ain’t there a better solution for this?

Answer 1

I would say

request.getRequestURL() + "/my/url"

makes the job. There is no such built in functionality, spring:url calls UrlTag.class that has the below method to generate URL, you can use it as an insőiration for your code:

private String createUrl() throws JspException {
    HttpServletRequest request = (HttpServletRequest) pageContext.getRequest();
    HttpServletResponse response = (HttpServletResponse) pageContext.getResponse();
    StringBuilder url = new StringBuilder();
    if (this.type == UrlType.CONTEXT_RELATIVE) {
        // add application context to url
        if (this.context == null) {
            url.append(request.getContextPath());
        }
        else {
            url.append(this.context);
        }
    }
    if (this.type != UrlType.RELATIVE && this.type != UrlType.ABSOLUTE && !this.value.startsWith("/")) {
        url.append("/");
    }
    url.append(replaceUriTemplateParams(this.value, this.params, this.templateParams));
    url.append(createQueryString(this.params, this.templateParams, (url.indexOf("?") == -1)));

    String urlStr = url.toString();
    if (this.type != UrlType.ABSOLUTE) {
        // Add the session identifier if needed
        // (Do not embed the session identifier in a remote link!)
        urlStr = response.encodeURL(urlStr);
    }

    // HTML and/or JavaScript escape, if demanded.
    urlStr = isHtmlEscape() ? HtmlUtils.htmlEscape(urlStr) : urlStr;
    urlStr = this.javaScriptEscape ? JavaScriptUtils.javaScriptEscape(urlStr) : urlStr;

    return urlStr;
}