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Home/ Questions/Q 7922659
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T17:02:35+00:00 2026-06-03T17:02:35+00:00

I use the code below to handle ajax call erros. I would like to

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I use the code below to handle ajax call erros. I would like to add the line number of that '$('body').append(...' line to be abble to echo it out. By line number, I mean the line number within my .js file. Wondering if that is possible to get the actual line number? Thank you in advance for your replies. Cheers. Marc

$.ajax({
    type: "POST",
    url: "myfile.php",
    error: function(jqXHR, textStatus, errorThrown) {

        $('body').append('aj.ERROR! [' + jqXHR.status + ' : ' + errorThrown + ']');
    },
    success: function(data) {
        // somecode
    }
});​
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T17:02:38+00:00Added an answer on June 3, 2026 at 5:02 pm

    The only way I know to expose the current line number is with the window.onerror event handler, which has this signature:

    window.onerror = function(msg, url, line) { ... }
    

    so in theory you could trigger a real error in your code (throw ?) and then do your append in the error handler, e.g:

    window.onerror = function(msg, url, line) {
        $('body').append(msg + ' at ' + url + ':' + line);
    };
    
    $.ajax({
        type: "POST",
        url: "myfile.php",
        error: function(jqXHR, textStatus, errorThrown) {
            throw 'aj.ERROR! [' + jqXHR.status + ' : ' + errorThrown + ']';
        },
        success: function(data) {
            // somecode
        }
    });​
    

    EDIT it works (in Chrome, at least…) – http://jsfiddle.net/alnitak/gLzY2/

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