I use the example provided in confint help page
> fit <- lm(100/mpg ~ disp + hp + wt + am, data=mtcars)
> summary(fit)
Call:
lm(formula = 100/mpg ~ disp + hp + wt + am, data = mtcars)
Residuals:
Min 1Q Median 3Q Max
-1.6923 -0.3901 0.0579 0.3649 1.2608
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 0.740648 0.738594 1.003 0.32487
disp 0.002703 0.002715 0.996 0.32832
hp 0.005275 0.003253 1.621 0.11657
wt 1.001303 0.302761 3.307 0.00267 **
am 0.155815 0.375515 0.415 0.68147
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 0.6754 on 27 degrees of freedom
Multiple R-squared: 0.8527, Adjusted R-squared: 0.8309
F-statistic: 39.08 on 4 and 27 DF, p-value: 7.369e-11
> confint(fit)
2.5 % 97.5 %
(Intercept) -0.774822875 2.256118188
disp -0.002867999 0.008273849
hp -0.001400580 0.011949674
wt 0.380088737 1.622517536
am -0.614677730 0.926307310
> confint(fit, "wt")
2.5 % 97.5 %
> wt 0.3800887 1.622518
>confint.default(fit,"wt")
2.5 % 97.5 %
wt 0.4079023 1.594704
> 1.001303 + 1.96*0.302761
[1] 1.594715
> 1.001303 - 1.96*0.302761
[1] 0.4078914
So the 95% CI obtained from confint.default is based on asymptotic normality. What about for confint?
Thanks
You can check out the code for each method.
The difference appears to be that default uses normal quantiles and the method for linear models uses T-quantiles instead.