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Home/ Questions/Q 8721383
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T07:12:46+00:00 2026-06-13T07:12:46+00:00

I use the following code to get content from my table. But I need

  • 0

I use the following code to get content from my table.
But I need to change the output of the JSON a little bit.

$rows = array();
if(isset($_GET['fruitName'])) {
$stmt = $pdo->prepare("SELECT variety FROM fruit WHERE name = ? ORDER BY variety");
$stmt->execute(array($_GET['fruitName']));
$rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
}
echo json_encode($rows);

With the above code it show it like this:

[{"variety":"Apple"},{"variety":"Banana"},{"variety":"Orange"},{"variety":"Pear"}]

But I want it to be like this:

[{"optionValue": "Apple", "optionDisplay": "Apple"}, {"optionValue": "Banana", "optionDisplay": "Banana"}, {"optionValue": "Orange", "optionDisplay": "Orange"}, {"optionValue": "Pear", "optionDisplay": "Pear"}]
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T07:12:47+00:00Added an answer on June 13, 2026 at 7:12 am

    One solution could be to adjust the SQL-query like this:

    SELECT variety AS optionValue, variety AS optionDisplay FROM fruit WHERE name = ? ORDER BY variety
    

    Another approach would be to parse each row individually and build up your array by hand. So instead of

    $rows = $stmt->fetchAll(PDO::FETCH_ASSOC);
    

    you could use

    $rows = array();
    while( $row = $stmt->fetch(PDO::FETCH_ASSOC) ) {
      $rows[] = array( 'optionValue' => $row['variety'], 'optionDisplay' => $row['variety'] );
    }
    
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