Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 1056817
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 16, 20262026-05-16T17:46:15+00:00 2026-05-16T17:46:15+00:00

I use the following code to run ls -l ./ and get the result

  • 0

I use the following code to run “ls -l ./” and get the result in scratch buffer.

(start-process "my-process" "*scratch*" "ls" "-l" "./")
  • How can I get the result in clipboard or something (kill ring or whatever) so that I can easily copy the result whenever necessary?
  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-16T17:46:16+00:00Added an answer on May 16, 2026 at 5:46 pm

    You can adjust this to your liking:

    (kill-new (shell-command-to-string "ls -l ."))
    

    The call to kill-new will put the string from shell-command-to-string on the kill ring.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I've got the following code that I can't seem to get working: function drawTable($result)
I have following code snippet that i use to compile class at the run
I have an array of objects, and i use following code to get in
How can I run a ruby piece of code from a buffer, without actually
I'm trying to use the following code to run a PL/SQL statement on my
How can i modify the following code to run in a synchronous way ?
I use following code: Create a retry policy, when error, retry after 1 second,
I just use following code to add an image to my project, var paper
I use VS2010, C# to develop Silverlight 4 app, I use following code in
I use the following code to crop an image according to a rectangular selection

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.