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Home/ Questions/Q 935079
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T21:06:07+00:00 2026-05-15T21:06:07+00:00

I use the following function to show a status message after a form submit

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I use the following function to show a status message after a form submit from my asp.net page.. The function gets called but it(alertmsg div) doesn’t seem to show up why?

 function topBar(message) {
        var $alertdiv = $('<div id = "alertmsg"/>');
        $alertdiv.text(message);
        alert($alertdiv);
        alert($alertdiv.text(message));
        $alertdiv.click(function() {
            $(this).slideUp(200);
        });
        $(document.body).append($alertdiv);
        setTimeout(function() { $alertdiv.slideUp(200) }, 5000);
    }

What happens is both the alert statements show [Object object]… I think both need to show different outputs… Any suggestion..

css:

#alertmsg
{
  font-family:Arial,Helvetica,sans-serif;
   font-size:135%;
   font-weight:bold;
  overflow: hidden;
  width: 100%;
  text-align: center;
  position: absolute;
  top: 0;
  left: 0;
  background-color: #404a58;
  height: 0;
  color: #FFFFFF;
  font: 20px/40px arial, sans-serif;
  opacity: .9;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T21:06:08+00:00Added an answer on May 15, 2026 at 9:06 pm

    You’re alerting the jQuery object. Try changing your alert to:
    alert($alertdiv.get(0).innerText);

    Other than that, your div may not be showing because you’re adding the click event before you add the div element to the page.

    Try changing:

    $alertdiv.click(function() {
                $(this).slideUp(200);
            });
    

    To:

    $alertdiv.bind('click', function() {
                $(this).slideUp(200);
            });
    

    or even:

    $alertdiv.live('click', function() {
                $(this).slideUp(200);
            });
    

    I think this may be the only way to bind dynamically generated elements. I’ve never tried .click() outside of the document ready function.

    Edit:
    In addition to the above suggestion for jQuery, your css should be changed to specify a height for the div. Your height of 0 will cause it to render, technically, and possibly slide up. But, you won’t be able to see it because it is 0 pixels tall at point 0,0.

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